Acetic Acid Water Vapor Liquid Equilibrium

$SOLVED:Vapor-liquid equilibrium data in mole fractions for the system acetone-air-water at 1 atm (101.3 kPa) are as follows: y, acetone in air: 0.004 0.008 0.014 0.017 0.019 0.020 x, acetone in water: 0.002 0.004 0.006 0.008 0.010 0.012 (a) Plot the data as (1) a graph of moles acetone per mole air versus moles acetone per mole water, (2) partial pressure of acetone versus g acetone per g water, and (3) y versus x. (b) If 20 moles of gas$

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SOLVED:Vapor-liquid equilibrium data in mole fractions for the system acetone-air-water at 1 atm (101.3 kPa) are as follows: y, acetone in air: 0.004 0.008 0.014 0.017 0.019

VIDEO ANSWER: Vapor-liquid equilibrium data in mole fractions for the system acetone-air-water at 1 atm (101.3 kPa) are as follows: \begin{array}{lllllll}y, \t…

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SOLVED:Explain how the equilibrium vapor pressure of a liquid might be measured.

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$A solution of acetic acid (CH3COOH) and water that is 90.% acetic acid by mass is boiling at 109.8 $^\circ$C. The vapor is collected and cooled until it condenses to form a new solution.Calculate the percent by mass of acetic acid in the new solution. Here's some data you may need:normalboilingpointdensityvaporpressure at109.8 ^∘Cacetic acid118. ^∘C(g)/(mL)1.1648. torrwater100. ^∘C(g)/(mL)1.001061. torrBe sure your answer has 2 significant digits.Note for advanced students: you may assume the so$